Joe Bunting
To Alain White 1945
#2
( 6 + 5 )
|
Solution:
1.Qc6 ! (2.Qxc5 #)
1...Kc4 2.Rxb4 #
1...Ke5 2.Qd6 #
1...Ke3 2.Qe4 #
1...Se4 2.Qxe4 #
1...B~ 2.Bf2 # |
Ofer Comay
2009
#3
( 9 + 8 )
|
Solution:
1.Sf3! (2.Bf2 #)
1...Rd6+ 2.Kf4!
1...Rc6+ 2.Ke4!
1...Ra6+ 2.Kd3!
1...Rxb7+ 2.Ke4!
1...Rb5+ 2.Kd3!
1...Rb4+ 2.Kd2! |
Milan Vukcevic
3rd Prize Olympic Tourney, Thesaloniki 1984
#4
( 10 + 7 )
|
Solution:
1.Sg4! (2.Sc3#)
1...Rxg4 2.Kb1! Qb7+ 3.Rb4+
1...Bxg4 2.Ka1! Qf6+ 3.Re4+ |
Ofer Comay
Mat Plus 2008
H#2 b) wBc8-->a4 ( 5 + 6 )
|
Solution:
a) 1.Kf5 Rxd7 2.Se7+ Rd5#
b) 1.Ke6 Bxc6 2.d5+ Bd7# |
Petko Petkov
2nd Prize Stella Polaris 1969
S#3
( 10 + 12 )
|
Solution:
1.Bf7! 2.e8=Q+ Qxd8 3.Qe5+
1...Qxd8 2.e8=S+ Qxe8 3.Sxe4+
1...Sc3 2.e8=B+ Qxd8 3.Rxd6+
1...Kxf7 2.e8=R+ Kg6 3.Qg5+ |
Jean Michel Trillon
Themes 64 1981
#5 Circe
( 6 + 2 )
|
In "Circe" when a piece is captured it returns to its birth
place. If the birth square is occupied the piece is removed from
the board.
Solution:
Set play
1...Ke4 2.Ba3 Kf4 3.Bc1+ Ke4 4.Kd2 Kf4 5.Kde#
Sol:
1.Kd2! Ke4 2.Bf8 Kf4 3.Bh6+ Ke4 4.Bf4! Kxf4 (Bc1) 5.Kd3# |
Uri Avner & Yuri
Berezhnoy
2nd Prize Phenix 1993
S#3
( 10 + 14 )
|
Solution:
1.Ke6! 2.Sb6+ Bxb6 3.Qd5+
1...Bg2,f1 2.Rc5+ Bxc5 3.Qd5+
1...Bxf5+ 2.Kd6+ Be6 3.Se5+
1...Rxg6+ 2.Kd7+ Re6 3.Rc5+ |
D. Petrov
1932
win
( 4 + 3 )
|
Solution:
1.Bc1 Rf2+ 2.Kg3 Rf1 3.Bf4+ Rxf4
4.Bd3 ! Rd4/Rb4 5.Sb5+/Sd5+ wins |